challenge-algorithms-v2.0-desafio-Affonso-Kopmann/08-isAnagram/index.js

export function isAnagram(word1, word2) {
  // implementar logica aqui
  if (cleanString(word1) === cleanString(word2)) {
    return true;
    } else {
      return false;
    };
}
  function cleanString(str) {
    return str.toLowerCase().split('').sort().join();
  }