export function mostUsedChar(text) {
    // implementar logica aqui
    const value = text.toLocaleLowerCase().split("").sort();

    let counts = {};
    value.forEach(function (x) {
        counts[x] = (counts[x] || 0) + 1;
    });

    const maior = Object.keys(counts).sort(function (a, b) {
        return counts[a] > counts[b] ? -1 : counts[b] > counts[a] ? 1 : 0;
    })[0];

    return maior;
}